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0.75x^2-2.25x-3=0
a = 0.75; b = -2.25; c = -3;
Δ = b2-4ac
Δ = -2.252-4·0.75·(-3)
Δ = 14.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.25)-\sqrt{14.0625}}{2*0.75}=\frac{2.25-\sqrt{14.0625}}{1.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.25)+\sqrt{14.0625}}{2*0.75}=\frac{2.25+\sqrt{14.0625}}{1.5} $
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